单选题 较易0.85 引用3 组卷276
根据下列热化学方程式
C(s) + O2(g) = CO2(g) △H1=–393.5 kJ·mol-1
2H2(g) + O2(g) =2H2O(l) △H2=–571.6 kJ·mol-1
CH3COOH(l) +2O2(g)=2CO2 (g) + 2H2O(l) △H3=–870.3 kJ·mol-1
可以计算出2C(s) + 2H2(g)+ O2(g)=CH3COOH(l)的反应热为:
C(s) + O2(g) = CO2(g) △H1=–393.5 kJ·mol-1
2H2(g) + O2(g) =2H2O(l) △H2=–571.6 kJ·mol-1
CH3COOH(l) +2O2(g)=2CO2 (g) + 2H2O(l) △H3=–870.3 kJ·mol-1
可以计算出2C(s) + 2H2(g)+ O2(g)=CH3COOH(l)的反应热为:
A.△H=+244.1 kJ·mol-1 | B.△H=-488.3 kJ·mol-1 |
C.△H=-996.6 kJ·mol-1 | D.△H=+996.6 kJ·mol-1 |
18-19高一下·浙江宁波·期中
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已知下列热化学方程式:
①CH3COOH(l)+2O2(g)=2CO2(g) +2H2O(l) ΔH1=﹣870.3 kJ·mol-1
②C(s) +O2(g) =CO2(g) ΔH2=﹣393.5 kJ·mol-1
③H2(g) +O2(g) =H2O(l) ΔH3=﹣285.8 kJ·mol-1
则反应2C(s) +2H2(g) +O2(g)=CH3COOH(l)的焓变ΔH为
①CH3COOH(l)+2O2(g)=2CO2(g) +2H2O(l) ΔH1=﹣870.3 kJ·mol-1
②C(s) +O2(g) =CO2(g) ΔH2=﹣393.5 kJ·mol-1
③H2(g) +O2(g) =H2O(l) ΔH3=﹣285.8 kJ·mol-1
则反应2C(s) +2H2(g) +O2(g)=CH3COOH(l)的焓变ΔH为
A.﹣488.3 kJ·mol-1 | B.﹣224.15 kJ·mol-1 |
C.488.3 kJ·mol-1 | D.244.15 kJ·mol-1 |
已知下列反应的热化学方程式为
①CH3COOH(l)+2O2(g)=2CO2(g)+2H2O(l) ΔH1=-870.3 kJ·mol-1
②C(s)+O2(g)=CO2(g) ΔH2=-393.5 kJ·mol-1
③H2(g)+ O2(g)=H2O(l) ΔH3=-285.8 kJ·mol-1
则反应2C(s)+2H2(g)+O2(g)=CH3COOH(l)的ΔH为
①CH3COOH(l)+2O2(g)=2CO2(g)+2H2O(l) ΔH1=-870.3 kJ·mol-1
②C(s)+O2(g)=CO2(g) ΔH2=-393.5 kJ·mol-1
③H2(g)+ O2(g)=H2O(l) ΔH3=-285.8 kJ·mol-1
则反应2C(s)+2H2(g)+O2(g)=CH3COOH(l)的ΔH为
A.-207 kJ·mol-1 | B.-488.3 kJ·mol-1 |
C.-1549.6 kJ·mol-1 | D.-476.8 kJ·mol-1 |
已知下列反应的热化学方程式为
①CH3COOH(l)+2O2(g)=2CO2(g)+2H2O(l) ΔH1=-870.3kJ·mol-1
②C(s)+O2(g)=CO2(g) ΔH2=-393.5kJ·mol-1
③H2(g)+O2(g)=H2O(l) ΔH3=-285.8kJ·mol-1
则反应2C(s)+2H2(g)+O2(g)=CH3COOH(l)的ΔH为( )
①CH3COOH(l)+2O2(g)=2CO2(g)+2H2O(l) ΔH1=-870.3kJ·mol-1
②C(s)+O2(g)=CO2(g) ΔH2=-393.5kJ·mol-1
③H2(g)+O2(g)=H2O(l) ΔH3=-285.8kJ·mol-1
则反应2C(s)+2H2(g)+O2(g)=CH3COOH(l)的ΔH为( )
A.-488.3kJ·mol-1 |
B.-191kJ·mol-1 |
C.-476.8kJ·mol-1 |
D.-1549.6kJ·mol-1 |
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